How do you sketch the graph of #y=(-x-2)^2# and describe the transformation?

1 Answer
Feb 21, 2018

First, you have to use Binomial Multiplication (FOIL)

Explanation:

That first step is crucial. Many people will just distribute the square across the expression inside the parenthesis, but that is incorrect.

So, #(-x-2)^2->(-x-2)(-x-2)->x^2+2x+2x+4#

So, #x^2+4x+4#

This is a parabola that opens up. The x coordinate of the vertex of a parabola can be found by #{-b}/{2a}#, so #{-4}/{2*1}=-2#

To get the y coordinate for the vertex, plug the -2 into your equation:

#(-2)^2+4(-2)+4->4-8+4=0#

So, the vertex is at (-2,0)