How do you sketch the graph of #y=-x^2# and describe the transformation?

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Answer 1 · 2017-12-28T01:05:25

Refer Explanation Section.

Given -

#y=-x^2#

There is no constant term in the given equation. Hence it passes through the origin.

Take a few points less than and greater than zero. These are the likely values variable #x# is going to assume. Find the corresponding values of #y#

Tabulate them as follows.
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Graph them

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The curve takes a turn at #x=0#