How do you sketch the graph of #y=(x+6)^2-2# and describe the transformation?

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Answer 1 · 2018-03-20T08:16:05

See explanation.

The graph of a function given in a form:

#y=a(x-p)^2+q#

can be obtained from the graph of

by translating it by a vector #vec(v)=[p;q]#

In the given example we have:

#a=1#, #p=-6# and #q=-2#

So we have to translate #y=x^2# by #vec(v)=[-6,-2]#

graph{(y-x^2)(y-(x+6)^2+2)=0 [-10, 10, -5, 5]}