# How do you solve 0 = x^2 + 4x + 4  graphically and algebraically?

Aug 10, 2016

$x = - 2$

#### Explanation:

Algebraically: factorise and then solve each factor = 0.

$\left(x + 2\right) \left(x + 2\right) = 0$

$x + 2 = 0 \Rightarrow x = - 2 \text{ both give the same answer}$

Graphically:
Draw the graph of $\textcolor{b l u e}{y} = {x}^{2} + 4 x + 4$
This will be a parabola.

To solve ${x}^{2} + 4 x + 4 = \textcolor{b l u e}{0}$ , read the point(s) from the graph where the parabola cuts the $x$-axis.

The $x$-axis is the line where $\textcolor{b l u e}{y = 0}$

The parabola will intersect (touch) at only point where $x = - 2$graph{x^2+4x+4 [-10, 10, -5, 5]}