# How do you solve #1/2a+1/3b=8, 3/2a-4/3b=-4#?

##### 1 Answer

Dec 31, 2016

Solution is

#### Explanation:

The two given are equations are

**...................................(1)** and

**...................................(2)**

Multiplying **(1)** by

**...................................(3)**

and subtracting **(2)** from **(3)**, we get

or

or

Putting **(1)**, we get

or

or

i.e.

Hence, solution is