Question

How do you solve `1/3(4x+3)>=2/3x+2`?

Answer 1

You may multiply by a positive number, say `3`:

Explanation:

`cancel3xx1/cancel3(4x+3)>=cancel3xx2/cancel3x+2->`

`4x+3>=2x+2->` now subtract `2x`

`4x-2x+3>=cancel(2x)-cancel(2x)+2->` now subtract `3`

`2x+cancel3-cancel3>=2-3->2x>=-1->x>=-1/2`