How do you solve #(1+53)\div 2#?

1 Answer
Dec 31, 2016

Answer:

#((1+53))/2 = (54)/2 =27#

Explanation:

Use BODMAS (Brackets Orders Division Multiplication Addition And Subtraction. First, add the numbers in the bracket because it's the first, the B, in BODMAS.

#1+53=54#

Then if there's nothing else left in the bracket, move to the outside.

#(54)/2#

Because we only have division left we simply divide #54# by #2#

#54/2=27#

Note: if there were other signs besides division, we'd work them out like this:

#(53+1)/2 + 7 * 4#

would be

Bracket first

#53+1=54#

Then division

#54/2=27#

Then multiplication

#7 * 4=28#

This is what it looks like at this stage

#27+28#

Now simply add the two

#27+28=55#