# How do you solve 1/(6a) + 1/(3a^2) = 1/(3a) and find any extraneous solutions?

Mar 19, 2017

$\frac{a}{6 {a}^{2}} + \frac{2}{6 {a}^{2}} = \frac{2 a}{6 {a}^{2}}$

$a + 2 = 2 a$

$2 = 2 a - a$

$a = 2$

It's worth noting that $a \ne 0$.

Hopefully this helps!