How do you solve #10+a^2=-7a#?
Since we have a second-degree term, we know we are dealing with a quadratic, so we need to set it equal to zero to find its zeroes.
We can add
At this point, we want to think of two numbers that sum up to the middle term (
After some trial and error, we arrive at
Setting both factors equal to zero, we get
Hope this helps!