How do you solve #10x^2 - 19x + 6 = 0# using the quadratic formula?

1 Answer
Aug 4, 2018

Answer:

#x = (19 + 2sqrt19)/20# and #x = (19 - 2sqrt19)/20#

Explanation:

#10x^2 - 19x + 6 = 0#

The quadratic formula is #x = (-b +- sqrt(b^2 - 4ac))/(2a)#.

We know that: #a = 10#, #b = -19#, and #c = 6# based on the equation, so let's plug them into the formula:
#x = (-(-19) +- sqrt((-19)^2 - 4(10)(6)))/(2(10))#

#x = (19 +- sqrt(361 - 240))/20#

#x = (19 +- sqrt76)/20#

#x = (19 +- sqrt(4*19))/20#

#x = (19 +- 2sqrt19)/20#

Hope this helps!