How do you solve $10x+43<13$ ?

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Answer 1 · 2015-05-07T20:17:01

The answer is $x<-3$ .

Solve $10x+43<13$ .

Isolate the $x$ term on one side by subtracting 43 from both sides.

$10x+43-43<13-43$ =

$10x<-30$

Divide both sides by $10$ .

$(10x)/10<-30/10$ =

$x<-3$

How do you solve 10x+43<1310x+43<13?