How do you solve #11>5-3x#?

1 Answer
Jan 9, 2017

Answer:

See full solution process below in the Explanation section:

Explanation:

First, subtract #color(red)(5)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#11 - color(red)(5) > 5 - 3x - color(red)(5)#

#11 - color(red)(5) > 5 - color(red)(5) - 3x#

#6 > 0 - 3x#

#6 > -3x#

Next, we will divide each side of the equation by #color(blue)(-3)# to solve for #x# while keeping the inequality balanced. However, because this is an inequality and we are dividing or multiplying by a negative number we must reverse the inequality:

#6/color(blue)(-3) color(red)(<) (-3x)/color(blue)(-3)#

#-2 color(red)(<) (color(blue)(cancel(color(black)(-3)))x)/cancel(color(blue)(-3))#

#-2 < x#

Now, to solve in terms of #x# we reverse or "flip" the entire inequality:

#x > -2#