# How do you solve 11>5-3x?

Jan 9, 2017

See full solution process below in the Explanation section:

#### Explanation:

First, subtract $\textcolor{red}{5}$ from each side of the inequality to isolate the $x$ term while keeping the inequality balanced:

$11 - \textcolor{red}{5} > 5 - 3 x - \textcolor{red}{5}$

$11 - \textcolor{red}{5} > 5 - \textcolor{red}{5} - 3 x$

$6 > 0 - 3 x$

$6 > - 3 x$

Next, we will divide each side of the equation by $\textcolor{b l u e}{- 3}$ to solve for $x$ while keeping the inequality balanced. However, because this is an inequality and we are dividing or multiplying by a negative number we must reverse the inequality:

$\frac{6}{\textcolor{b l u e}{- 3}} \textcolor{red}{<} \frac{- 3 x}{\textcolor{b l u e}{- 3}}$

$- 2 \textcolor{red}{<} \frac{\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{- 3}}} x}{\cancel{\textcolor{b l u e}{- 3}}}$

$- 2 < x$

Now, to solve in terms of $x$ we reverse or "flip" the entire inequality:

$x > - 2$