How do you solve 12(1−4x)=18?
1 Answer
Jul 31, 2016
Explanation:
Divide both sides by
1−4x=1812=32
Add
−12=4x
For any Real value of
If we had wanted
2−1=12=4x=(22)x=22x
and hence solution
We can make this into a set of Complex solutions for our original problem by adding an odd multiple of
Let
Then:
4x=4−12+(2k+1)πiln(4)
=4−12⋅4(2k+1)πiln(4)
=12⋅(eln(4))(2k+1)πiln(4)
=12⋅eln(4)⋅(2k+1)πiln(4)
=12⋅e(2k+1)πi
=12⋅(eπi)2k+1
=12⋅(−1)2k+1
=−12