# How do you solve 12<-4(3c-6) and graph the solution on a number line?

Jul 24, 2018

$c < 1$

#### Explanation:

$12 < - 4 \left(3 c - 6\right)$

Distribute the right side:
$12 < - 12 c + 24$

Add $\textcolor{b l u e}{12 c}$ to both sides:
$12 \quad \textcolor{b l u e}{+ \quad 12 c} < - 12 c \quad + \quad 24 \quad \textcolor{b l u e}{+ \quad 12 c}$

$12 + 12 c < 24$

Subtract $\textcolor{b l u e}{12}$ from both sides:
$12 + 12 c \quad \textcolor{b l u e}{- \quad 12} < 24 \quad \textcolor{b l u e}{- \quad 12}$

$12 c < 12$

Divide both sides by $\textcolor{b l u e}{12}$:
$\frac{12 c}{\textcolor{b l u e}{12}} < \frac{12}{\textcolor{b l u e}{12}}$

$c < 1$

Here is a graph of it on a number line:

The open circle on $1$ means that $1$ is not a solution (but anything less than it is).

Hope this helps!