How do you solve #12|x/4+11|= 60#?

1 Answer
Jul 25, 2016

Answer:

x = - 24 , x = - 64

Explanation:

There are 2 parts to solve here.

First divide both sides by 12

#(cancel(12)^1|x/4+11|)/cancel(12)^1=60/12=5#

(1) solve #x/4+11=5rArrx/4=-6#

multiply both sides by 4

#cancel(4)^1xxx/cancel(4)^1=-6xx4rArrx=-24#

and (2) solve #x/4+11=-5" and proceed as before"#

#rArrx/4=-16rArrx=-64#

Thus solutions are x = -24 and x = -64