# How do you solve 12h+30<10h-45?

Jul 11, 2017

#### Answer:

Solve as you would an equation, but with the inequality in place of the equal symbol.

$h = - \frac{75}{2}$

#### Explanation:

Solve:

$12 h + 30 < 10 h - 45$

Subtract $30$ from both sides.

$12 h + \textcolor{red}{\cancel{\textcolor{b l a c k}{30}}} - \textcolor{red}{\cancel{\textcolor{b l a c k}{30}}} < 10 h - 45 - 30$

Simplify.

$12 h < 10 h - 75$

Subtract $10 h$ from both sides.

$12 h - 10 h < \textcolor{red}{\cancel{\textcolor{b l a c k}{10 h}}} - \textcolor{red}{\cancel{\textcolor{b l a c k}{10 h}}} - 75$

Simplify.

$2 h < - 75$

Divide both sides by $2$.

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} h}{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}}} < - \frac{75}{2}$

Simplify.

$h < - \frac{75}{2}$