# How do you solve # 12x^2 - 25x + 12 > =0#?

##### 1 Answer

#### Answer:

(-inf.,

#### Explanation:

First solve f(x) = 0 to find its 2 real roots, using the new Transforming Method (Google, Yahoo Search).

Transformed equation f'(x) = x^2 - 25x + 144 = 0.

Find 2 real roots, that have the same sign, knowing their sum (-b = 25) and their product (ac = 144).

Factor pairs of (ac = 144) --> (6, 24)(8, 18)(9, 16). This last sum is (25 = -b). Consequently, the 2 real roots of f'(x) are: 9 and 16.

Back to f(x), its 2 real roots are:

Now, plot the 2 roots

Solution set by intervals,

Half closed intervals (-inf.,

The 2 end points are included in the solution set.

Graph:

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