How do you solve #13x-11<=7x+37#?

1 Answer
Feb 11, 2017

Answer:

See the entire solution process below:

Explanation:

First, add #color(red)(11)# and subtract #color(blue)(7x)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#13x - 11 + color(red)(11) - color(blue)(7x) <= 7x + 37 + color(red)(11) - color(blue)(7x)#

#13x - color(blue)(7x) - 11 + color(red)(11) <= 7x - color(blue)(7x) + 37 + color(red)(11)#

#6x - 0 <= 0 + 48#

#6x <= 48#

Now, divide each side of the inequality by #color(red)(6)# to solve for #x# while keeping the inequality balanced:

#(6x)/color(red)(6) <= 48/color(red)(6)#

#(color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6)) <= 8#

#x <= 8#