How do you solve $15g+18>13g-2>=6+15g$ ?

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Answer 1 · 2018-07-05T06:55:07

$-10 < g ≤ -4$

Do

$i) \ 15g + 18 > 13g - 2$

$15g - 13g > -18 - 2$

$2g > -20$

$g > -10$

and

$ii) \ 13g-2 ≥ 6 + 15g$

$13g - 15g ≥ 2 + 6$

$-2g ≥ 8$

$g ≤ -4 ->$ [division by a negative number = sign change]

How do you solve 15g+18>13g-2>=6+15g15g+18>13g-2>=6+15g?