# How do you solve 16x^2 - 9 = 0 by factoring?

It is 16x^2-9=0=>(4x)^2-3^2=0=>(4x-3)*(4x+3)=0=> x=3/4 or x=-3/4
We used the identity ${a}^{2} - {b}^{2} = \left(a - b\right) \cdot \left(a + b\right)$