How do you solve #(18-n)^(1/2)=(n/8)^(1/2)#?

1 Answer
Sep 22, 2017

Answer:

#n = 16#

Explanation:

This is much easier to solve than it first appears. Notice that both powers are the same on each side of the equality. If the powers are the same and they are equal, the the bases must also be equal. Therefore:

#(18 - n ) = (n/8)#

So solve for #n#:

#18 - n = n/8 => 144 -8n = n => 144 = 9n => n = 144/9=> n=16#

Check:

#(18-16)^(1/2) = (16/8)^(1/2)#

#2^(1/2)= 2^(1/2)#