How do you solve #18u^2-3u=1#?
can be determined using the quadratic formula (see bottom, if you don't know this formula).
If we recognize that (after moving the 1 to the left side) we can factor:
I use the new AC Method (Google, Yahoo Search)
Factor pairs of (-18)--> (-2, 9)(-3, 6). This sum is 3 = -b
p' = 3 and q' = - 6
Factored form: y = 18(x + 1/6)(x - 1/3) =