Question

How do you solve `18x^2-50=0`?

Answer 1

`x=+-5/3`

Explanation:

`"add 50 to both sides"`

`rArr18x^2=50`

`"divide both sides by 18"`

`rArrx^2=50/18=25/9`

`color(blue)"take the square root of both sides"`

`rArrx=+-sqrt(25/9)larrcolor(blue)"note plus or minus"`

`rArrx=+-5/3`