How do you solve #19 < 7 + 1/3k + 2 -2/3k#?

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Answer 1 · 2015-05-12T04:05:35

Solve #19<7+1/3k+2-2/3k# .

Combine like terms.

#19<7+2+1/3k-2/3k# =

#19<9-1/3k#

Simplify #1/3k# to #k/3#.

#19<9-k/3#

Multiply both sides times #3#.

#19*3<9*3-k# =

#57<27-k#

Subtract #27 from both sides.

#57-27<27-27-k# =

#30<-k#

Multiply both sides times #-1#. This will cause the inequality to be reversed.

#-30>k#

Flip to get #k# on the left side.

#k<-30#