How do you solve $2<= -1+m$ ?

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Answer 1 · 2017-03-20T12:42:08

See the entire solution process below:

First, add $color(red)(1)$ to each side of the inequality to isolate and solve for the $m$ term while keeping the inequality balanced:

$color(red)(1) + 2 <= color(red)(1) - 1 + m$

$3 <= 0 + m$

$3 <= m$

To put this solution in terms of $m$ we need to reverse or "flip" the inequality:

$m >= 3$

How do you solve 2<= -1+m2<= -1+m?