How do you solve #2( 2w + 5) + 2w = 146#?

3 Answers
Jan 8, 2018

Answer:

#w=68/3#

Explanation:

#"distribute the bracket on the left side of the equation"#

#4w+10+2w=146#

#rArr6w+10=146#

#"subtract 10 from both sides"#

#6wcancel(+10)cancel(-10)=146-10#

#rArr6w=136#

#"divide both sides by 6"#

#(cancel(6) w)/cancel(6)=136/6#

#rArrw=68/3" is the solution"#

Jan 8, 2018

Answer:

#color(red)(w=22.67)#

Explanation:

1) Using BIDMAS or respectively BODMAS or similar, B stands for brackets, so first you multiply the bracket:

#color(red)(2*2w=4w)#
#color(red)(2*5=10)#

2) Re-input this into the equation, removing the brackets:

#therefore# #color(green)(4w+10+2w=146)#

3) Collecting like terms give us:

#color(blue)(6w+10=146)#

4) Solve like an equation:

#color(blue)(6w=136)(-10)#

#color(blue)(w=136/6=22.666...)#

#color(red)(w=22.67)#

Jan 8, 2018

Answer:

#w=68/3#

Explanation:

Given:#color(white)("d")2(2w+5)+2w=146#

divide everything on both sides of the = by 2 giving:

#2w+5+w=73#

#3w+5=73#

Subtract 5 from both sides

#3w=68#

Divide both sides by 3

#w=68/3#