# How do you solve  2-3[7-2(4-x)]= 2x-1?

Jan 8, 2016

$x = \frac{3}{4}$

#### Explanation:

this is a multi-step equation.

the first step is to simplify the contents of the 'square bracket'

$2 - 3 \left(7 - 8 + 2 x\right) = 2 x - 1$

now simplify contents of 'new bracket'

$2 - 3 \left(- 1 + 2 x\right) = 2 x - 1$

now multiply the bracket by - 3

$2 + 3 - 6 x = 2 x - 1$

now collect like terms to separate sides of the = sign

$2 + 3 + 1 = 2 x + 6 x$

$6 = 8 x$ ( divide both sides by 8 to obtain x )

$\frac{6}{8} = \frac{8 x}{8} \Rightarrow x = \frac{3}{4}$