How do you solve $2-3[7-2(4-x)]= 2x-1$ ?

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Answer 1 · 2016-01-08T14:35:37

$x = 3/4$

this is a multi-step equation.

the first step is to simplify the contents of the 'square bracket'

$2 -3 ( 7- 8 + 2x ) = 2x - 1$

now simplify contents of 'new bracket'

$2 - 3 ( - 1 + 2x ) = 2x - 1$

now multiply the bracket by - 3

$2 + 3 - 6x = 2x - 1$

now collect like terms to separate sides of the = sign

$2 + 3 + 1 = 2x + 6x$

$6 = 8x$ ( divide both sides by 8 to obtain x )

$6/8 = (8x)/8 rArr x = 3/4$

How do you solve 2-3[7-2(4-x)]= 2x-1 2-3[7-2(4-x)]= 2x-1?