How do you solve #2/3(a-3)=1/3#? Algebra Linear Equations Multi-Step Equations with Like Terms 1 Answer Tom Jun 13, 2015 #a = 7/2# Explanation: First we need to "delete" #2/3# by multiplying both side by the inverse of #2/3 => (2/3)^-1=3/2# #=>a-3=1/2# and then add #3# both side #=>a = 1/2 + 3 = 7/2# Finally we have #a = 7/2# Answer link Related questions How do you solve multi step equations by combining like terms? How do you solve multi step equation #w + w + 12 = 40#? How do you solve #3p + 4p + 37 = 79#? How do you solve for f: #f-1+2f+f-3=-4#? How do you combine like terms? How do you combine like terms for #-7mn-2mn^2-2mn + 8#? How do you combine like terms for #3x^2 + 21x + 5x + 10x^2#? What is a term? How do you solve #3v+5-7v+18=17#? How do you solve for x in #5x + 7x = 72#? See all questions in Multi-Step Equations with Like Terms Impact of this question 1481 views around the world You can reuse this answer Creative Commons License