How do you solve #2 + (3/(x-1)) = 10#?

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Answer 1 · 2016-03-10T02:39:39

You must start by putting on an equal denominator.

The LCD (least common denominator) is #x - 1#

#(2(x - 1))/(x - 1) + 3/(x - 1) = (10(x - 1))/(x - 1)#

We can now eliminate the denominators and solve.

#2x - 2 + 3 = 10x - 10#

#11 = 8x#

#11/8 = x#

Practice exercises:

#(2)/(2x + 3) + 3/(x - 1) = 5/(x - 1)#

Challenge problem:

Solve for x: #1/x + 1/(xy) = 2/(y + x)#

Good luck!