How do you solve #2/3 x+2>4#?

1 Answer
Mar 13, 2018

Answer:

Re-arrange the equation such that you get x by itself, such that the equation forms #x gt 3#

Explanation:

First, move the 2 to the right hand side by subtracting 2 from both sides:

#2/3x > 2#

Next, multiply both sides by the inverse of the fractional coefficient:

#2/3x*(3/2) > 2*(3/2) rArr color(red)(x > 3)#