How do you solve #2( 3x - 4) \geq 9x - 10#?
1 Answer
Oct 12, 2016
Explanation:
Distribute
#2(3x-4)≥9x-10 rarr 6x-8≥9x-10#
Subtract
#-8≥3x-10#
Add
#2≥3x#
Divide by
#2/3≥x#
Distribute
#2(3x-4)≥9x-10 rarr 6x-8≥9x-10#
Subtract
#-8≥3x-10#
Add
#2≥3x#
Divide by
#2/3≥x#