# How do you solve #2( 3x - 4) \geq 9x - 10#?

##### 1 Answer

Oct 12, 2016

#### Answer:

#### Explanation:

Distribute

#2(3x-4)≥9x-10 rarr 6x-8≥9x-10#

Subtract

#-8≥3x-10#

Add

#2≥3x#

Divide by

#2/3≥x#