How do you solve -2(4b+1)< -3b+8?

Apr 5, 2018

$b > - 2$

Explanation:

$- 2 \left(4 b + 1\right) < - 3 b + 8$

$- 8 b - 2 < - 3 b + 8$

$- 8 b + 3 b < 8 + 2$

$- 5 b < 10$

$\frac{- 5 b}{-} 5 < \frac{10}{-} 5$

$b > - 2$

The sign will change due to the fact that you divide both sides by a negative number.