How do you solve  -2 < 4z + 10 ≤ 12?

Jun 8, 2015

$- 2 < 4 z + 10 \le 12$
Subtract 10 from all the 3 members:
$- 2 - 10 < 4 z + 10 - 10 \le 12 - 10$
$- 12 < 4 z \le 2$
Devide by 4 all the three members:
$- 3 < z \le \frac{1}{2}$
That's all folks!