How do you solve $2.5 = ln(x)$ ?

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Answer 1 · 2015-07-29T21:01:11

$x=e^{2.5}approx 12.1825$

$log_{b}(c)=d$ is equivalent to $b^{d}=c$

Since $ln(x)=log_{e}(x)$ , $ln(x)=2.5$ is equivalent to $e^{2.5}=x$

How do you solve 2.5 = ln(x)2.5 = ln(x)?