How do you solve #2^x=0.5#?

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Aviv S. Share
Mar 10, 2018

Answer:

The answer is #x=-1#.

Explanation:

Rewrite #0.5# as #1/2#, then make the exponents equal each other.

#2^x=0.5#

#2^x=1/2#

#2^x=1/2^1#

#2^x=2^-1#

#2^color(red)x=2^color(red)(-1)#

#x=-1#

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Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

2
Mar 10, 2018

Answer:

#x=-1#

Explanation:

We know that for any #a^x=b#, #log_ab=x#

Here, #a=2# and #b=0.5#. So we take:

#log_2 0.5=-1#

So #x=-1#

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