How do you solve #-2<x+2<5#?

2 Answers
Apr 20, 2018

Answer:

See a solution process below

Explanation:

#-2 < x + 2 < 5#

Cross #2# to the right hand side..

#-2 < x < 5 - 2#

#-2 < x < 3#

Hence;

#x < 3#

The statement above indicates that #x# is less than #3#

#-2 < x or x > -2#

The statement above means that #-2# is less than #x or x# is greater than #-2#

Apr 20, 2018

Answer:

#x in(-4,3)#

Explanation:

#"subtract 2 from each interval"#

#-2color(red)(-2)< xcancel(+2)cancel(color(red)(-2))< 5color(red)(-2)#

#rArr-4< x <3#

#rArrx in(-4,3)larrcolor(blue)"in interval notation"#