How do you solve #–2(x – 3) ≥ 5 – (x + 3)#?

1 Answer
May 18, 2018

Answer:

#4 ≥ x#

#x# is less than 4.

Explanation:

#-2(x - 3) ≥ 5 - (x + 3)#

First, distribute. #x# and #-3# will be multiplied by -2 because they're in parentheses, per PEMDAS. The #-# will be distributed to #x# and #3# because they're also in parentheses.

#-2x + 6 ≥ 5 -x -3#

Combine like terms.

#-2x + 6 ≥ 2 - x#

Now, negate the smallest variable. In this case, it's -2x, so add 2x to both sides to cancel it out.

#6 ≥ 2 + x#

Now, subtract 2 from both sides to isolate for x:

#4 ≥ x#

#x# is less than 4.