# How do you solve -2+(x-3) <= 7?

##### 2 Answers
May 9, 2017

$x \le 12$

#### Explanation:

First, add $2$ to both sides:

$- 2 + \left(x - 3\right) + 2 \le 7 + 2$

This becomes:

$x - 3 \le 9$

Now add $3$ to both sides:

$x - 3 + 3 \le 9 + 3$

This becomes:

$x \le 12$

May 9, 2017

See a solution process below:

#### Explanation:

First, remove the terms within parenthesis being careful to handle the sign of the individual terms correctly:

$- 2 + x - 3 \le 7$

Next, group and combine like terms on the left side of the inequality:

$x - 3 - 2 \le 7$

$x + \left(- 3 - 2\right) \le 7$

$x + \left(- 5\right) \le 7$

$x - 5 \le 7$

Now, add $\textcolor{red}{5}$ to each side of the inequality to solve for $x$ while keeping the inequality balanced:

$x - 5 + \textcolor{red}{5} \le 7 + \textcolor{red}{5}$

$x - 0 \le 12$

$x = 12$