How do you solve #-2+(x-3) <= 7#?

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Answer 1 · 2017-05-09T00:34:26

#x<=12#

First, add #2# to both sides:

#-2+(x-3)+2<=7+2#

This becomes:

#x-3<=9#

Now add #3# to both sides:

#x-3+3<=9+3#

This becomes:

#x<=12#

Answer 2 · 2017-05-09T00:35:27

See a solution process below:

First, remove the terms within parenthesis being careful to handle the sign of the individual terms correctly:

#-2 + x - 3 <= 7#

Next, group and combine like terms on the left side of the inequality:

#x - 3 - 2 <= 7#

#x + (-3 - 2) <= 7#

#x + (-5) <= 7#

#x - 5 <= 7#

Now, add #color(red)(5)# to each side of the inequality to solve for #x# while keeping the inequality balanced:

#x - 5 + color(red)(5) <= 7 + color(red)(5)#

#x - 0 <= 12#

#x = 12#