How do you solve #2(x + 8) ^ (4/5) - 12 = 150# and find any extraneous solutions?

1 Answer
Jul 30, 2016

Answer:

#x=235#

Explanation:

#2(x+8)^(4/5)-12=150#
or
#2(x+8)^(4/5)=150+12#
or
#2(x+8)^(4/5)=162#
or
#(x+8)^(4/5)=162/2#
or
#(x+8)^(4/5)=81#
or
#(x+8)=81^(5/4)#
or
#x+8=(root4(81))^5#
or
#x+8=(root4((3)(3)(3)(3)))^5#
or
#x+8=3^5#
or
#x+8=243#
or
#x=243-8#
or
#x=235#