# How do you solve 20p^2-15p=0?

Feb 8, 2017

$p = 0$ or $p = \frac{3}{4}$

#### Explanation:

the equation:
$20 {p}^{2} - 15 p = 0$

if you put that in brackets:
$5 p \left(4 p - 3\right) = 0$

now you can calculate that:
$5 p = 0$ or $4 p - 3 = 0$
$p = 0$ or $4 p = 3 \to p = \frac{3}{4}$