How do you solve $25^{x} - 28 = 97$ $25^x-28=97$ ?

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Answer 1 · 2016-07-30T16:36:35

$x = 1.5$ $x=1.5$

$25^{x} - 28 = 97$ $25^x-28=97$ or

$25^{x} = 97 + 28$ $25^x=97+28$ or

$25^{x} = 125$ $25^x=125$ or

${(5^{2})}^{x} = 5^{3}$ $(5^2)^x=5^3$ or

$5^{2 x} = 5^{3}$ $5^(2x)=5^3$ or

$2 x = 3$ $2x=3$

and $x = \frac{3}{2} = 1.5$ $x=3/2=1.5$

How do you solve 25^x-28=9725x−28=9725^x-28=97?