# How do you solve 2c+13=19?

Jun 12, 2017

See a solution process below:

#### Explanation:

Step 1) Subtract $\textcolor{red}{13}$ from each side of the equation to isolate the $c$ term while keeping the equation balanced:

$2 c + 13 - \textcolor{red}{13} = 19 - \textcolor{red}{13}$

$2 c + 0 = 6$

$2 c = 6$

Step 2) Divide each side of the equation by $\textcolor{red}{2}$ to solve for $c$ while keeping the equation balanced:

$\frac{2 c}{\textcolor{red}{2}} = \frac{6}{\textcolor{red}{2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} c}{\cancel{\textcolor{red}{2}}} = 3$

$c = 3$

Jun 12, 2017

$c = 3$

#### Explanation:

We need to move all terms that don't contain $c$ to the right side and solve.

$2 c + 13 = 19$

-subtract $13$ from each side

$2 c \cancel{+ 13 - 13} = 19 - 13$

$2 c = 6$

-divide each side by $2$

$c = 3$