# How do you solve 2d ^ { 2} + 29d - 15= 0?

Jul 21, 2017

$\frac{1}{2}$ and - 15

#### Explanation:

Use the new Transforming Method (Google Search):
$f \left(d\right) = 2 {d}^{2} + 29 d - 15 = 0$
Transformed equation:
$f ' \left(d\right) = {d}^{2} + 29 d - 30 = 0$
Proceeding: Find 2 real roots of f'(d), then, divide them by a = 2.
Since a + b + c = 0, use shortcut. The 2 real roots are: 1 and
$\frac{c}{a} = - 30$.
Back to f(d) --> The 2 real roots are: $x 1 = \frac{1}{a} = \frac{1}{2}$ and
$x 2 = - \frac{30}{a} = - \frac{30}{2} = - 15$