Question

How do you solve `2d ^ { 2} + 29d - 15= 0`?

Answer 1

`1/2` and - 15

Explanation:

Use the new Transforming Method (Google Search):
`f(d) = 2d^2 + 29d - 15 = 0`
Transformed equation:
`f'(d) = d^2 + 29d - 30 = 0`
Proceeding: Find 2 real roots of f'(d), then, divide them by a = 2.
Since a + b + c = 0, use shortcut. The 2 real roots are: 1 and
`c/a = -30`.
Back to f(d) --> The 2 real roots are: `x1 = 1/(a) = 1/2` and
`x2 = -30/a = -30/2 = - 15`