How do you solve #2e^x-1=7#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Roy D. May 31, 2018 # x = ln(4) \approx 1.386294361... # Explanation: # 2e^x-1+1 = 7+ 1 = 8 # # \frac{2e^x}{2} = \frac{8}{2} = 4 # #ln(e^x) = ln(4) # # x = ln(4) # Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2391 views around the world You can reuse this answer Creative Commons License