First, add #color(red)(4)# to each side of the equation to isolate the radical term while keeping the equation balanced:
#2root(3)(7b - 1) - 4 + color(red)(4) = 0 + color(red)(4)#
#2root(3)(7b - 1) - 0 = 4#
#2root(3)(7b - 1) = 4#
Next, divide each side of the equation by #color(red)(2)# to isolate the radical while keeping the equation balanced:
#(2root(3)(7b - 1))/color(red)(2) = 4/color(red)(2)#
#(color(red)(cancel(color(black)(2)))root(3)(7b - 1))/cancel(color(red)(2)) = 2#
#root(3)(7b - 1) = 2#
Then, cube each side of the equation to eliminate the radical while keeping the equation balanced:
#(root(3)(7b - 1))^color(red)(3) = 2^color(red)(3)#
#7b - 1 = 8#
Next, add #color(red)(1)# to each side of the equation to isolate the #b# term while keeping the equation balanced:
#7b - 1 + color(red)(1) = 8 + color(red)(1)#
#7b - 0 = 9#
#7b = 9#
Now, divide each side of the equation by #color(red)(7)# to solve for #b# while keeping the equation balanced:
#(7b)/color(red)(7) = 9/color(red)(7)#
#(color(red)(cancel(color(black)(7)))b)/cancel(color(red)(7)) = 9/7#
#b = 9/7#
