# How do you solve | 2x + 1 | <3x + 2?

$x > - \frac{3}{5}$
| 2x + 1 | <3x + 2->{(2x+1 < 3x + 2->x > -1), (2x+1 < -3x-2->x > -3/5):}
The more restrictive is $x > - \frac{3}{5}$ so is the solution