# How do you solve 2x+11<=5x-10?

Mar 26, 2018

$7 \le x$

#### Explanation:

What you want to do is eliminate $x$ to one side of the inequality (get it alone)
$2 x + 11 \le 5 x - 10$
$2 x + 11 \left(+ 10\right) \le 5 x - 10 \left(+ 10\right)$
$2 x + 21 \le 5 x$
$2 x + 21 \left(- 2 x\right) \le 5 x \left(- 2 x\right)$
$21 \le 3 x$
$21 \div i \mathrm{de} 3 \le 3 x \div i \mathrm{de} 3$
$7 \le x$