How do you solve $- 2 x + 16 \leq 35 - 16$ $-2x + 16\leq 35- 16$ ?

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Answer 1 · 2016-11-19T13:59:08

$x \geq - \frac{3}{2}$ $x >= -3/2$

Perform the necessary mathematics to isolate and solve for $x$ $x$ while keeping the inequality balanced.

First, subtract 16 from each side of the inequality:

$- 2 x + 16 - 16 \leq 35 - 16 - 16$ $-2x + 16 - 16 <= 35 - 16 - 16$

$- 2 x + 0 \leq 35 - 32$ $-2x + 0 <= 35 - 32$

$- 2 x \leq 3$ $-2x <= 3$

Next divide each side by $- 2$ $-2$ . Because we are multiplying or dividing by a negative number the inequality needs to be reversed:

$\frac{- 2 x}{- 2} \geq \frac{3}{- 2}$ $(-2x)/-2 >= 3/(-2)$

$1 x \geq - \frac{3}{2}$ $1x >= -3/2$

$x \geq - \frac{3}{2}$ $x >= -3/2$

How do you solve −2x+16≤35−16-2x + 16\leq 35- 16?