How do you solve #2x^2-13x-7=0#?

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Answer 1 · 2016-03-22T18:04:26

#x = -1/2 or 7#

#2x^2-13x-7=0#
can be factored to
#(2x+1)(x-7)=0#
set each factor equal to zero and solve for #x#
#2x+1=0#

#2x+1-1=0-1#

#2x=-1#

#(cancel2x)/cancel2 =-1/2#

#x = -1/2#

#x-7=0#

#x-7+7=0+7

#x=7#

#x = -1/2 or 7#