How do you solve #2x^2+18=0#?
1 Answer
Jul 2, 2018
Explanation:
#"subtract 18 from both sides"#
#2x^2=-18#
#x^2=(-18)/2=-9#
#x=+-sqrt(-9)=+-3i#
#"subtract 18 from both sides"#
#2x^2=-18#
#x^2=(-18)/2=-9#
#x=+-sqrt(-9)=+-3i#